20x^2-2x+15=10

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Solution for 20x^2-2x+15=10 equation: 



20x^2-2x+15=10

We move all terms to the left:

20x^2-2x+15-(10)=0

We add all the numbers together, and all the variables

20x^2-2x+5=0

a = 20; b = -2; c = +5;
Δ = b2-4ac
Δ = -22-4·20·5
Δ = -396
Delta is less than zero, so there is no solution for the equation

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